Question for Carl Moreland

[Zocky-Zocky]

Hi Carl!
Please answer me the following question:
In its Report on LRL device H3Tec you wrote the following:

"For gold, you will find that the NMR frequency is 1.754000MHz, and that this entry includes the statement "relative to 1H = 100 (MHz)". What this means is that whatever conditions produce an NMR frequency of 100MHz for hydrogen will produce an NMR frequency of 1.754MHz for gold. It turns out the NMR frequency for any given element is dependent on the applied (or ambient) magnetic field the element is exposed to. To make hydrogen precess at 100MHz requires a field strength of roughly 2.35 Teslas (T), so this becomes the reference field strength for all other elements. The NMR frequency is proportional to the magnetic field, so a field strength of 4.7T will result in an NMR frequency of 200MHz for hydrogen.
In treasure hunting, we are looking for e.g. buried gold that is subjected to the Earth's natural magnetic field. This varies from place-to-place, but 50 microTeslas (uT) is a fair average strength. So the reference field strength of 2.35T is a whopping 47,000 times stronger than the Earth's field. Working the other way, we can find that the NMR frequency of hydrogen exposed to the Earth's field is a mere 2.13kHz. Gold, with an NMR frequency of 1.754MHz at 2.35T, will have an NMR frequency of only 37Hz or so at 50uT."


The question is:
Please write a mathematical procedure or formula that you got that gold has frequency of 37 hertz magnetic influence of the earth from an average of 0.5 micro Tesla.

End:
If gold is then frekfrenciju of 37 hertz, how much, due to the influence of the earth's magnetic field of 0.5 mT, then had the following metals:
- Silver
- Copper,
- Lead and
- Iron?

Carl!
Most beautiful you please answer my questions!
Thank in advance!
Your admirer
Zocky-Zocky