Quote:
Originally Posted by BigDRN
From reading the previous posts concerning frequency calculation I understand how to calculate a frequency using the NMR combined with the total field. (Thanks carl for the formula!) My question has to do with combined elements. For instance I can calculate the frequency for pure gold, but the gold coins that I search for are 90% gold and 10 % copper. The same goes for silver coins. Is there a formula or process for determining the frequency for combinations of elements? What if the gold is buried in a container - how do you compensate for the container?
Also, some say that there are NMR frequencies for non - elements like diamonds or paper currency. Do you have a source for these frequencies (or know how to get them?)
Thank you in advance for any input that you can give.
Dave
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While this is not a useful technique for treasure hunting, there is a theoretical answer. Any compound can be pinged for precession. For example, in a proton mag water (or a hydrocarbon) is pinged, but it is the hydrogen atoms which dominate the resulting precession even though the oxygen atom makes up the bulk of the water molecule.
The reason for this is because hydrogen has a "receptivity factor" that is 90,000 times greater than oxygen. That is, for a given alignment field strength, hydrogen will create a precession signal that is 90,000 times stronger than oxygen. This becomes a classical summation of two signals, a 2128Hz 'H' signal and a 288Hz 'O' signal (assumes 50uT):
2*sin(2*PI*2128 ) + 0.0000111*sin(2*PI*288 )
The "2" in the H term is because there are 2 H's for every O.
If we pretend this is useful for treasure hunting, then to hunt for gold coins you would actually want to hunt for copper, since copper has a receptivity factor 2346 times higher than gold. So even though there is 9 times more gold than copper in the coin, the overall precession strength is 261x in favor of copper.
Diamond is ~pure carbon, an element. Paper money is mostly carbon.